A water treatment plant is built with three cylindrical tanks to contain the water for a town. Each tank has a radius of 16 feet and a depth of 22 feet.
If there are about 7.5 gallons in a cubic foot of water, approximately how many gallons of water can be treated at the plant at any one time?
The volume of each cylindrical tank can be calculated using the formula for the volume of a cylinder: V = πr^2h, where r is the radius and h is the height.
For each tank:
radius (r) = 16 feet
depth (h) = 22 feet
Using the formula, the volume of each tank is:
V = π(16^2)(22) = 14080π cubic feet
To convert this to gallons, we need to multiply by the conversion factor of 7.5 gallons per cubic foot:
Volume in gallons = 14080π * 7.5 = 105600π gallons
Using the approximation π ≈ 3.14, we can calculate the approximate volume in gallons for each tank:
Volume in gallons ≈ 105600 * 3.14 ≈ 331824 gallons
Since there are three tanks, the total volume of water that can be treated at the plant at any one time is approximately:
3 * 331824 gallons = 995472 gallons
Therefore, approximately 995,472 gallons of water can be treated at the plant at any one time.