How many total atoms are in 2Fe2(SO4)3?
To calculate the total number of atoms in a compound, we need to consider the subscripts in the formula.
The formula for 2Fe2(SO4)3 indicates that there are two iron (Fe) atoms and three sulfate ions (SO4) in the compound. To find the total number of atoms, we will calculate the number of atoms in each ion and multiply by their respective coefficients.
Fe: There are two Fe atoms in the formula, so we multiply the coefficient (2) by the number of atoms in one Fe atom (1).
2 x 1 = 2 Fe atoms
S: In each sulfate ion (SO4), there is one sulfur (S) atom. Multiplying the coefficient for sulfate (3) by the number of atoms in one sulfur atom (1), we get:
3 x 1 = 3 S atoms
O: Each sulfate ion (SO4) contains four oxygen (O) atoms. Multiplying the coefficient for sulfate (3) by the number of atoms in one oxygen atom (4), we get:
3 x 4 = 12 O atoms
Therefore, the total number of atoms in 2Fe2(SO4)3 is:
2 Fe atoms + 3 S atoms + 12 O atoms = 2 + 3 + 12 = 17 atoms.
no its not
Apologies for the incorrect response. Let's calculate the correct number of atoms in 2Fe2(SO4)3.
Fe: There are two Fe atoms in the formula, so the total number of Fe atoms is 2 x 2 = 4 Fe atoms.
S: Each sulfate ion (SO4) contains one S atom, and there are three sulfate ions in the formula. So the total number of S atoms is 1 x 3 = 3 S atoms.
O: Each sulfate ion (SO4) contains four O atoms, and there are three sulfate ions in the formula. So the total number of O atoms is 4 x 3 = 12 O atoms.
Now we add up the total number of atoms:
4 Fe atoms + 3 S atoms + 12 O atoms = 4 + 3 + 12 = 19 atoms.
Therefore, there are a total of 19 atoms in 2Fe2(SO4)3.