What is the weight of 50.0 L of SiF4 at STP?
To find the weight of SiF4 at STP, we need to know the molar mass of SiF4.
The molar mass of SiF4 can be found by adding up the atomic masses of its constituents: Si (28.0855 g/mol) and F (18.9984 g/mol). Since SiF4 has four fluorine atoms, we multiply the molar mass of F by 4.
Molar mass of SiF4 = (28.0855 g/mol) + 4 * (18.9984 g/mol) = 104.0797 g/mol
At STP (Standard Temperature and Pressure):
- Temperature = 0 degrees Celsius or 273.15 Kelvin
- Pressure = 1 atmosphere or 101.325 kPa
Using the ideal gas law, PV = nRT, where P = pressure, V = volume, n = number of moles, R = ideal gas constant, and T = temperature.
Since we want to find the weight, we need to convert the volume to moles using the molar mass:
Number of moles = (50.0 L) / [(22.414 L/mol) (1 mol / 1000 L)] = 2.24 mol
Weight = Number of moles * Molar mass
Weight = 2.24 mol * 104.0797 g/mol
Weight = 232.782 g
Therefore, the weight of 50.0 L of SiF4 at STP is 232.782 grams.