Lewis is rolling a 10-sided die 250 times. Each side of the die is labeled with a number 1 - 10 Based on the theoretical probability, how many times would Lewis be expected to roll a multiple of 3?
25
30
75
83
There are 3, 6, and 9 which are multiple of 3, so there are 3 possible outcomes out of 10 when rolling the die that are multiples of 3.
The probability of rolling a multiple of 3 is 3/10.
The expected value can be found by multiplying the probability of each outcome by the number of trials.
Expected value = (probability of rolling a multiple of 3) * (number of trials)
Expected value = (3/10) * (250)
Expected value = 75
Therefore, Lewis would be expected to roll a multiple of 3 75 times. Answer: \boxed{75}.