A boxer throws a punch with a force of 1,400 N that lasts 0.02 s. What is the impulse of this punch? (1 point) Responses 70,000 kg⋅m/s 70,000 kilograms times meters per second 7,000 kg⋅m/s 7,000 kilograms times meters per second 280 kg⋅m/s 280 kilograms times meters per second 28 kg⋅m/s
The impulse of an object is given by the product of its force and the time interval over which the force is applied. Mathematically, impulse = force × time.
In this case, the force is 1,400 N and the time interval is 0.02 s. Plugging these values into the equation, we get:
Impulse = 1,400 N × 0.02 s
= 28 kg⋅m/s
Therefore, the impulse of this punch is 28 kg⋅m/s.