It takes 50mL of 0.30M of sodium hydroxide ( NaOH
) to neutralize 15mL of carbonic acid ( H2CO3
) for the following chemical reaction:
2NaOH + H2CO3 → Na2CO3 + 2H2O
The concentration of the carbonic acid is ___________.
According to the balanced chemical equation, we can see that the ratio between the amount of NaOH and H2CO3 is 2:1.
Since it takes 50mL of 0.30M NaOH to neutralize 15mL of H2CO3, we can set up a proportion to find the concentration of H2CO3.
(0.30M NaOH) / (2) = X / (15mL)
X = (0.30M NaOH)(15mL) / (2)
X ≈ 0.0375M
Therefore, the concentration of carbonic acid (H2CO3) is approximately 0.0375M.