If figure PQRS is translated 6 units up and 4 units to the left, what are the coordinates of point S′
s= (2, 2)
To translate figure PQRS 6 units up and 4 units to the left, we will subtract 6 from the y-coordinate and 4 from the x-coordinate of point S.
The new coordinates can be found by subtracting 6 from 2 in the y-coordinate and subtracting 4 from 2 in the x-coordinate:
s' = (2 - 4, 2 - 6) = (-2, -4)
Therefore, the coordinates of point S' are (-2, -4).