standard form that passes through (0,-1) and (-6,-9)
To find the standard form of a linear equation passing through the points (0, -1) and (-6, -9), we can use the point-slope form of a linear equation.
The point-slope form is given by y - y₁ = m(x - x₁), where m is the slope and (x₁, y₁) is a point on the line.
First, let's find the slope (m) of the line using the two given points:
m = (y₂ - y₁) / (x₂ - x₁)
= (-9 - (-1)) / (-6 - 0)
= (-9 + 1) / (-6)
= -8 / (-6)
= 4 / 3
Now we have the slope (m) as 4/3. Let's choose the point (0, -1) as (x₁, y₁).
Plugging the values into the point-slope form:
y - (-1) = (4/3)(x - 0)
y + 1 = (4/3)x
To convert it to the standard form, we need to eliminate fractions. Multiply both sides of the equation by 3 to get rid of the fraction:
3y + 3 = 4x
Rearranging the terms to match the standard form Ax + By = C:
4x - 3y = -3
Therefore, the standard form of the linear equation passing through (0, -1) and (-6, -9) is 4x - 3y = -3.