Find the product of -x^2 + 2x - 5 and 3x + 2
______x^3 + _______x^2 + _________x + _________
A, 3.
B, -3.
C, 4.
D, -4.
E, 10.
F, -10.
G, 11.
H, -11.
To find the product of -x^2 + 2x - 5 and 3x + 2, we can use the distributive property:
(-x^2 + 2x - 5) * (3x + 2)
= -x^2 * 3x + 2x * 3x - 5 * 3x + -x^2 * 2 + 2x * 2 - 5 * 2
= -3x^3 + 6x^2 - 15x - 2x^2 + 4x - 10
= -3x^3 + (6x^2 - 2x^2) + (4x - 15x) - 10
= -3x^3 + 4x^2 - 11x - 10
So the product is:
x^3 + 4x^2 - 11x - 10
Therefore, the correct answer is H, -11.
You're supposed to use the numbers given to solve the problem
Apologies for the confusion. Let's solve the problem using the given numbers.
The given expression is -x^2 + 2x - 5 multiplied by 3x + 2.
To multiply these two expressions, we need to distribute each term of the first expression to each term of the second expression and then combine like terms.
So we have:
(-x^2 + 2x - 5) * (3x + 2)
= -x^2 * 3x + -x^2 * 2 + 2x * 3x + 2x * 2 - 5 * 3x - 5 * 2
= -3x^3 + -2x^2 + 6x^2 + 4x - 15x - 10
= -3x^3 + 4x^2 - 11x - 10
The final expression is -3x^3 + 4x^2 - 11x - 10.
Therefore, the correct answer is H, -11.