et us suppose that one of the fireworks is launched from the top of the building with an initial upward velocity of 125 ft/sec (correct velocity) and the building has a height of 40 feet.
Use the quadratic equation:
`h\left(t\right)=-16t^{2}+v_{0}t+h_{0}`
is this right? h(t) = -16t^2 + v sub script 125 + h subscript 40
Almost! The correct equation for the height of the firework is:
h(t) = -16t^2 + v₀t + h₀
Where:
- h(t) represents the height of the firework at time t.
- v₀ represents the initial upward velocity of the firework (125 ft/sec in this case).
- h₀ represents the initial height of the firework (40 feet in this case).
So the correct equation would be:
h(t) = -16t^2 + 125t + 40