equation 1: 2x-4y=16
equation 2: y=-3/4x-3
equation 3: y-5=-2(x+1)
which statement is true:
line three has a decrease in graph line one has the steepest slow blind one has the biggest Y intercept 1 2 has the biggest y-intercept line 3 has the least steep slope and line two has an increasing graph
Based on the given equations:
1. Equation 1: 2x - 4y = 16
2. Equation 2: y = -3/4x - 3
3. Equation 3: y - 5 = -2(x + 1)
The correct statement is:
- Line 2 (equation 2) has the biggest y-intercept.
Explanation:
- For line 1 (equation 1): 2x - 4y = 16, to find the y-intercept, set x = 0 and solve for y:
2(0) - 4y = 16
-4y = 16
y = -4.
So, the y-intercept for line 1 is -4.
- For line 3 (equation 3): y - 5 = -2(x + 1), to find the y-intercept, set x = 0 and solve for y:
y - 5 = -2(0 + 1)
y - 5 = -2
y = 3.
So, the y-intercept for line 3 is 3.
- For line 2 (equation 2): y = -3/4x - 3, the equation is already in the slope-intercept form (y = mx + b) where m is the slope and b is the y-intercept. In this case, the y-intercept, b, is -3.
Comparing the y-intercepts:
- Line 1 has a y-intercept of -4.
- Line 2 has a y-intercept of -3.
- Line 3 has a y-intercept of 3.
Therefore, line 2 (equation 2: y = -3/4x - 3) has the biggest y-intercept among the given equations.