Suppose that 76% of the area under a standard normal curve is to the left of a
-score. What portion of the area is between the mean and the
-score?
Since 76% of the area is to the left of a score, this means that 24% of the area is to the right of the score (100% - 76%).
Since the standard normal curve is symmetric, this means that 12% of the area is between the mean (center) and the score (12%/2 = 6% on each side).
Therefore, the portion of the area between the mean and the score is 6%.