There are two different cats. The first vat has 12 gallons is being filled at a rate of 2 gallons per minute.
The second cat has 136 gallons and is leaking fluid at a rate of 6 gallons per minute. After how many seconds will both cats have the same amount of liquid
__minutes
Let's assume that after t minutes, both cats will have the same amount of liquid.
For the first cat, the amount of liquid can be represented by the equation: 12 + 2t.
For the second cat, the amount of liquid can be represented by the equation: 136 - 6t.
Setting the two equations equal to each other:
12 + 2t = 136 - 6t.
Combining like terms:
8t = 124.
Dividing both sides by 8:
t = 15.5.
So, after 15.5 minutes, both cats will have the same amount of liquid.