Given Cos= -5/13 where 0<=theta<=360.
In which quadrant(s) would the terminal arm of theta lie?
To determine the quadrant(s) in which the terminal arm of θ would lie, we need to look at the sign of the cosine in each quadrant.
In the unit circle, cosine is negative in the second and third quadrants.
- In the second quadrant, both x and y coordinates are positive, so the terminal arm of θ would lie in this quadrant.
- In the third quadrant, x coordinate is negative and y coordinate is positive, so the terminal arm of θ would not lie in this quadrant.
Therefore, the terminal arm of θ would only lie in the second quadrant.