y-3=1/5(x-2)
what are the two point on the graph
it CANT be a decimal of a fraction
To find the points on the graph of the equation y-3=1/5(x-2), we need to substitute different values for x and solve for the corresponding values of y.
Let's choose two values of x and solve for y:
For x = 0:
Substituting x=0 into the equation, we have y-3=1/5(0-2)
Simplifying, we get y-3=1/5(-2)
Expanding, we have y-3=-2/5
Adding 3 to both sides, we get y = -2/5 + 3
Combining the fractions, y = -2/5 + 15/5 = 13/5
So, when x=0, y=13/5.
For x = 4:
Substituting x=4 into the equation, we have y-3=1/5(4-2)
Simplifying, we get y-3=1/5(2)
Expanding, we have y-3=2/5
Adding 3 to both sides, we get y = 2/5 + 3
Combining the fractions, y = 2/5 + 15/5 = 17/5
So, when x=4, y=17/5.
Therefore, the two points on the graph of the equation y-3=1/5(x-2) are (0, 13/5) and (4, 17/5).