In rabbits, white fur (W) is dominant to black (w), and long ears (E) are dominant to short ears (e). A breeder mates two rabbits that are heterozygous (WwEe) for both traits.
What is the chance that the offspring will be white with long ears?
(You may use the easy quick method to solve. Hint= set up 2 monohybrid crosses and multiply)
a
1/16
b
3/16
c
8/16
d
9/16
To determine the chance that the offspring will be white with long ears, we need to multiply the probabilities for each trait independently.
For fur color:
Since white fur (W) is dominant to black (w), there are three possible genotypes that could result in white fur: WW, Ww, Ww. Only one genotype (WW) will result in rabbits with white fur. Therefore, the probability of offspring having white fur is 1/4.
For ear length:
Since long ears (E) are dominant to short ears (e), there are three possible genotypes that could result in long ears: EE, Ee, Ee. Two out of the three genotypes (EE, Ee) will result in rabbits with long ears. Therefore, the probability of offspring having long ears is 2/4 or 1/2.
To find the overall probability, we multiply the probabilities for each trait: (1/4) * (1/2) = 1/8.
Therefore, the chance that the offspring will be white with long ears is 1/8.
However, none of the given options matches this answer. The closest option is 1/16, but this is not the correct answer based on the calculations.