3x + y = −2

3x + −2y = 10

To solve this system of equations, we can use the method of substitution.

From the first equation, we can isolate y:

3x + y = -2
y = -3x - 2

Substitute this expression for y in the second equation:

3x + (-2)(-3x - 2) = 10
3x + 6x + 4 = 10
9x + 4 = 10
9x = 6
x = 6/9
x = 2/3

Now substitute this value of x into the first equation to find y:

3(2/3) + y = -2
2 + y = -2
y = -4 - 2
y = -6

Therefore, the solution is x = 2/3 and y = -6.