What is the value of the range of the function f(x) = x² + 2 for the domain value 1/4? Show your work.
y = 2
y = 2 1/4
y = 2 1/8
y = 2 1/16
To find the range of the function, we need to substitute the given domain value into the function and calculate the corresponding range value.
So, for the domain value x = 1/4:
f(1/4) = (1/4)^2 + 2
= 1/16 + 2
= 1/16 + 32/16
= (1 + 32)/16
= 33/16
Therefore, the range value for the domain value x = 1/4 is y = 33/16.