Find the x and y- intercepts of - 6x + 3y = 36
A. x-intercept is (- 6, 0), y-intercept is (0, 3) B. x-intercept is (6, 0), y-intercept is (0, - 12) C. x-intercept is (- 6, 0), y-intercept is (0, 12)
D. x-intercept is (36, 0), y-intercept is (0, 36)
To find the x-intercept, we set y = 0 and solve for x. Plugging in y = 0 into the equation -6x + 3y = 36, we get -6x + 3(0) = 36, which simplifies to -6x = 36. Dividing both sides by -6, we get x = -6. Thus, the x-intercept is (-6, 0).
To find the y-intercept, we set x = 0 and solve for y. Plugging in x = 0 into the equation -6x + 3y = 36, we get -6(0) + 3y = 36, which simplifies to 3y = 36. Dividing both sides by 3, we get y = 12. Thus, the y-intercept is (0, 12).
Therefore, the correct answer is C. x-intercept is (-6, 0), y-intercept is (0, 12).