Consider the following quadratic equation:
−2x^2−4x=−5
Step 2 of 2 : Use the discriminant, b2−4ac
, to determine the number of solutions of the given quadratic equation. Then solve the quadratic equation using the formula x=−b±b2−4ac⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯/2a
The quadratic equation is given as −2x^2−4x=−5.
To find the discriminant, we can identify the values of a, b, and c in the standard quadratic equation form: ax^2 + bx + c = 0.
Here, a = -2, b = -4, and c = -5.
The discriminant (D) is given by the formula D = b^2 - 4ac.
Plugging in the values, we have:
D = (-4)^2 - 4(-2)(-5)
D = 16 - 40
D = -24
Since the discriminant (-24) is negative, there are no real solutions to the quadratic equation.