Question

6x2−17x+12 =0

for x

Answer 1

[AI-generated answer — Bot GPT 3.5]

To solve the equation 6x^2 - 17x + 12 = 0 for x, you can use the quadratic formula.

The quadratic formula states that for an equation of the form ax^2 + bx + c = 0, the solutions for x are given by:

x = (-b ± √(b^2 - 4ac)) / (2a)

In our case, a = 6, b = -17, and c = 12. Substituting these values into the equation, we get:

x = (-(-17) ± √((-17)^2 - 4(6)(12))) / (2(6))
x = (17 ± √(289 - 288)) / 12
x = (17 ± √1) / 12

Now, we can simplify this:

x = (17 + 1) / 12 = 18 / 12 = 3/2
x = (17 - 1) / 12 = 16 / 12 = 4/3

So the solutions for x are x = 3/2 and x = 4/3.