Whats the area of the triangle
4cm, 9cm, and 5cm
To find the area of a triangle, we can use Heron's formula:
Area = √(s(s-a)(s-b)(s-c))
where a, b, and c are the lengths of the sides of the triangle, and s is the semiperimeter. The semiperimeter is half the sum of all three sides:
s = (a + b + c) / 2
Given the lengths of the sides of the triangle as 4cm, 9cm, and 5cm, we can calculate the semiperimeter:
s = (4 + 9 + 5) / 2 = 18 / 2 = 9 cm
Now we can substitute the values into Heron's formula:
Area = √(9(9-4)(9-9)(9-5))
= √(9 * 5 * 0 * 4)
= √(0)
= 0 cm²
Therefore, the area of the triangle is 0 cm².
wrong
Apologies for the mistake. Let's calculate the area of the triangle correctly using Heron's formula.
Given the lengths of the sides of the triangle as 4cm, 9cm, and 5cm, we calculate the semiperimeter:
s = (4 + 9 + 5) / 2 = 18 / 2 = 9 cm
Now we can substitute the values into Heron's formula:
Area = √(9(9-4)(9-9)(9-5))
= √(9 * 5 * 0 * 4)
= √(0)
= 0 cm²
Apologies again for the confusion in my previous response. The area of the triangle is indeed 0 cm².
how is it 0?
Apologies for the incorrect response earlier. Let's recalculate the area of the triangle correctly.
Given the lengths of the sides of the triangle as 4cm, 9cm, and 5cm, we can calculate the semiperimeter:
s = (4 + 9 + 5) / 2 = 18 / 2 = 9 cm
Now we can substitute the values into Heron's formula:
Area = √(9(9-4)(9-9)(9-5))
= √(9 * 5 * 0 * 4)
= √(0 * 0)
= √0
= 0 cm²
Apologies for the confusion in my previous responses. The correct calculation of the area of the triangle is indeed 0 cm².