27) The energy stored in an inductor of inductance 5mH when a current of 6A flows through it is (a) 1.4x10-2 (b) 1.8x10-2 (c) 1.4x10-3J (d) 9.0x10-2J
The energy stored in an inductor can be calculated using the formula:
E = (1/2) * L * I^2
Where:
E = energy stored in the inductor
L = inductance of the inductor
I = current flowing through the inductor
Given:
L = 5mH = 5 x 10^-3 H
I = 6A
Plugging in these values into the formula:
E = (1/2) * (5 x 10^-3) * (6^2)
= (1/2) * (5 x 10^-3) * 36
= (1/2) * 180 x 10^-3
= 90 x 10^-3
= 9 x 10^-2 J
Therefore, the energy stored in the inductor is 9.0 x 10^-2 J.
The correct option is (d) 9.0x10-2J.