A club with twelve members is to choose three officers: president, vice-president, and secretary- treasurer. If each office is to be held by one person and no person can hold more than one office, in how many ways can those offices be filled.
There are 12 choices for the president. After one person is chosen, there are 11 choices for the vice-president, and after two people have been chosen, there are 10 choices for the secretary-treasurer. Multiplying these together, we find the answer is $12 \times 11 \times 10 = \boxed{1320}$.
