LM¯¯¯¯¯¯¯¯¯ is the midsegment of trapezoid ABCD. If AB =50 and DC = 135, what is the length of LM?
Since LM is the midsegment of trapezoid ABCD, we know that LM is parallel to both AB and DC.
Since LM is also the midsegment, it is equal in length to the average of the lengths of the two bases (AB and DC).
The length of LM is therefore equal to (AB + DC) / 2, or (50 + 135) / 2.
Calculating this expression gives us (185) / 2 = 92.5.
Therefore, the length of LM is 92.5.