A special right triangle drawn in Quadrant 1 intersects the unit circle at point (x, y) where y = 2√2 . What is the x-coordinate? (1 point) Responses 2√2 the fraction with numerator square root of 2 and denominator 2 3√2 the fraction with numerator square root of 3 and denominator 2 1 1 45 degrees
We know that the point (x, y) lies on the unit circle, which means that x^2 + y^2 = 1.
Since y = 2√2, we can substitute this into the equation above:
x^2 + (2√2)^2 = 1
x^2 + 8 = 1
x^2 = 1 - 8
x^2 = -7
Since x cannot be a negative imaginary number (as we are in Quadrant 1), we can conclude that the x-coordinate does not exist. Therefore, the answer is none of the provided options.