What is the surface area of a square pyramid with base length of 10 cm and slant height of 20 cm?(1 point)
cm2
The surface area of a square pyramid can be found by adding the area of the base to the sum of the areas of the four triangular faces.
The area of the base can be found by squaring the length of one side of the base. In this case, the base length is 10 cm, so the area of the base is 10 cm * 10 cm = 100 cm^2.
Each triangular face of the pyramid is an isosceles triangle with base length equal to the length of one side of the base and height equal to the slant height. In this case, the base length is 10 cm and the slant height is 20 cm.
The area of an isosceles triangle can be found by multiplying half the base length by the height. In this case, half the base length is 10 cm/2 = 5 cm.
Thus, the area of each triangular face is (5 cm) * (20 cm) / 2 = 50 cm^2.
Since there are four triangular faces, the total area of the pyramid is 4 * 50 cm^2 = 200 cm^2.
Therefore, the surface area of the square pyramid is 200 cm^2.