A)
For question 1, find the x- and y-intercept of the line.
-10x+5y=40
(1 point)
x-intercept is 5; y-intercept is .-10
x-intercept is 8; y-intercept is .-4
x-intercept is-10 ; y-intercept is 5.
x-intercept is -4; y-intercept is 8
To find the x-intercept, we set y = 0 and solve for x. Plugging in y = 0 into the equation -10x + 5y = 40, we get -10x + 5(0) = 40, which simplifies to -10x = 40. Solving for x, we divide both sides of the equation by -10, yielding x = -4. Therefore, the x-intercept is -4.
To find the y-intercept, we set x = 0 and solve for y. Plugging in x = 0 into the equation -10x + 5y = 40, we get -10(0) + 5y = 40, which simplifies to 5y = 40. Solving for y, we divide both sides of the equation by 5, yielding y = 8. Therefore, the y-intercept is 8.
Therefore, the x-intercept is -4 and the y-intercept is 8.
A)
For question 2, find the x- and y-intercept of the line.
5x + 4y = 80
(1 point)
x-intercept is 4; y-intercept is 5.
x-intercept is 20; y-intercept is 16.
x-intercept is 5; y-intercept is 4.
x-intercept is 16; y-intercept is 20
To find the x-intercept, we set y = 0 and solve for x. Plugging in y = 0 into the equation 5x + 4y = 80, we get 5x + 4(0) = 80, which simplifies to 5x = 80. Solving for x, we divide both sides of the equation by 5, yielding x = 16. Therefore, the x-intercept is 16.
To find the y-intercept, we set x = 0 and solve for y. Plugging in x = 0 into the equation 5x + 4y = 80, we get 5(0) + 4y = 80, which simplifies to 4y = 80. Solving for y, we divide both sides of the equation by 4, yielding y = 20. Therefore, the y-intercept is 20.
Therefore, the x-intercept is 16 and the y-intercept is 20.
A)
The grocery store sells kumquats for $4.75 a pound and Asian pears for $2.25 a pound.
Write an equation in standard form for the weights of kumquats k and Asian pears p that a
customer could buy with $22.
(1 point)
4.75k + 2.25p = 22
4.75k = 2.25p + 22
4.75 + 2.25 = k
4.75p + 2.25k = 22
To find the equation in standard form, we need to set up a linear equation that represents the weights of kumquats and Asian pears a customer could buy with $22.
Let's assume the customer buys k pounds of kumquats and p pounds of Asian pears.
The cost of the kumquats would be 4.75k and the cost of the Asian pears would be 2.25p.
The total cost of the purchase is $22, so we can write the equation as:
4.75k + 2.25p = 22.
Therefore, the equation in standard form for the weights of kumquats k and Asian pears p that a customer could buy with $22 is 4.75k + 2.25p = 22.