PLS CHECK MY ANSWERS!!
1.) Subtract 11/ 3 - 2v3
answer: The difference is 9√3
2.) Provide an exact answer.
Divide
V125
3/5
15)
answer: 5/3
3.) Rewrite the irrational cube root 189 as the product of an integer and another irrational cube root. Show your work.
ANSWER: The cube root of 189 can be expressed as the cube root of 27 times the cube root of 7, as 189 is equal to 27 multiplied by 7. The cube root of 27 is 3, so the expression becomes 3 times the cube root of 7. Therefore, the irrational cube root of 3 times the cube root of 189 can be written as 3 times the cube root of 7.
3√7 cubed
Your answers are partially correct.
1.) The correct answer is 11/3 - 2√3, as you cannot subtract a number and a radical directly.
2.) The correct answer in exact form is (√125) / (3/5) = (√125) * (5/3) = (5√125) / 3 = (5√(25*5)) / 3 = (5 * 5√5) / 3 = (25√5) / 3.
3.) The correct answer is 3√7^3 = 3^3 * √7^3 = 27√7^3 = 27√(7^2 * 7) = 27√(49 * 7) = 27 * 7√7 = 189√7.