Did I answer this problem right?
A bag contains 13 marbles of which 10 are red. A marble is selected at random and replaced. A second marble is then selected at random. What is the probability that both marbles are red?
100/169.
Thanks.
Correct.
To check if you answered the problem correctly, let's go through it step by step.
In the bag, there are 13 marbles, and 10 of them are red. The question asks for the probability that both marbles drawn are red.
To determine the probability, we need to consider the total number of possible outcomes and the number of favorable outcomes.
Step 1: Probability of selecting a red marble on the first draw:
Out of the 13 marbles, 10 are red. Therefore, the probability of selecting a red marble on the first draw is 10/13.
Step 2: Since the first marble is replaced, the bag still contains 13 marbles, with 10 of them being red. So, the probability of selecting a red marble on the second draw is also 10/13.
Step 3: To find the probability of both events occurring, we multiply the probabilities of each marble being red: (10/13) * (10/13) = 100/169.
So, according to your answer, the probability that both marbles are red is indeed 100/169. Well done!