sue is wrapping books to give as gifts. Book A has a side length of 6.5 inches, a width of 1 inch, and a height of 8.5 inches. Book B has a length of 5.5 inches, a width of 2 inches, and a height of 8 inches. based on surface area, which book will require less wrapping paper
To find the surface area of a rectangular prism, we need to find the area of each side and add them together.
For Book A:
- There are 2 sides with a length of 6.5 inches and a width of 1 inch, so the area of these two sides is 2 * 6.5 * 1 = 13 square inches.
- There are 2 sides with a length of 6.5 inches and a height of 8.5 inches, so the area of these two sides is 2 * 6.5 * 8.5 = 110.5 square inches.
- There are 2 sides with a width of 1 inch and a height of 8.5 inches, so the area of these two sides is 2 * 1 * 8.5 = 17 square inches.
The total surface area of Book A is 13 + 110.5 + 17 = 140.5 square inches.
For Book B:
- There are 2 sides with a length of 5.5 inches and a width of 2 inches, so the area of these two sides is 2 * 5.5 * 2 = 22 square inches.
- There are 2 sides with a length of 5.5 inches and a height of 8 inches, so the area of these two sides is 2 * 5.5 * 8 = 88 square inches.
- There are 2 sides with a width of 2 inches and a height of 8 inches, so the area of these two sides is 2 * 2 * 8 = 32 square inches.
The total surface area of Book B is 22 + 88 + 32 = 142 square inches.
Based on surface area, Book A requires less wrapping paper than Book B.