What is the correct answer when you solve −5x^2 + 2 + 8x = 0 using the quadratic formula? in approxiamation
To solve the equation −5x^2 + 2 + 8x = 0 using the quadratic formula, we first need to arrange the equation in the standard quadratic form, Ax^2 + Bx + C = 0, where A = -5, B = 8, and C = 2.
Using the quadratic formula, x = (-B ± √(B^2 - 4AC)) / (2A), we can substitute the values to find x.
x = (-(8) ± √((8)^2 - 4(-5)(2))) / (2(-5))
Simplifying further:
x = (-8 ± √(64 + 40)) / (-10)
x = (-8 ± √(104)) / (-10)
Approximating √(104) to two decimal places:
x = (-8 ± 10.20) / (-10)
Therefore, the approximate solutions are:
x1 ≈ (-8 + 10.20) / (-10) ≈ 0.22
x2 ≈ (-8 - 10.20) / (-10) ≈ -1.42
So, the correct approximations for the values of x that solve the equation are x ≈ 0.22 and x ≈ -1.42.