Carolyn usually only misses about 10% of her free throws. If she misses fewer than 2 of her next 4 free throws, then she will hold the school record for free throws.
To estimate the probability of this happening, Carolyn uses a computer to randomly select 4 numbers from 0 to 9. She lets 0 represent a missed free throw and 1 through 9 represent a made free throw.
She repeats this for a total of 18 trials and records the results in the table below.
8100 1347 0693 9869 3399 1376 1273 7905 3471
7987 7604 4587 2968 5064 2697 4248 4545 3308
What is the best estimate, based on this simulation, of the probability that she will miss fewer than 2 of her next 4 free throws?
Responses
6%
6%
33%
33%
67%
67%
94%
To estimate the probability, we need to count the number of times Carolyn misses fewer than 2 free throws out of the 18 trials. Looking at the numbers in the table, we can see that in 6 of the trials, the numbers selected are 0 or 1 (representing a missed or made free throw). Therefore, the best estimate of the probability that Carolyn will miss fewer than 2 of her next 4 free throws is 6 out of 18, which simplifies to 1/3 or 33%.
So, the correct answer is:
33%