Siobhan is making banana pudding. The recipe calls for 2 1/4 cups of heavy whipping cream and 14 1/2 ounces of sweetened condensed milk. The recipe makes 12 servings; Siobhan wants to reduce the recipe so that it only makes 4 servings. How much milk and cream will she need? Express the answers in the simplest form.
Apologies for the mistake. Let's redo the calculations.
For the heavy whipping cream: 2 1/4 / 3 = 9/4 / 3 = (9/4) * (1/3) = 9/12 = 3/4 cup
For the sweetened condensed milk: 14 1/2 / 3 = 29/2 / 3 = (29/2) * (1/3) = 29/6 = 4 5/6 ounces
Therefore, Siobhan will need 3/4 cup of heavy whipping cream and 4 5/6 ounces of sweetened condensed milk for 4 servings.
To determine how much milk and cream Siobhan will need for 4 servings, we need to reduce the amounts by a factor of 3. To find the amounts for the reduced recipe, we divide the original amounts by 3.
For the heavy whipping cream: 2 1/4 / 3 = 3/2 / 3 = 3/6 = 1/2 cup
For the sweetened condensed milk: 14 1/2 / 3 = 29/2 / 3 = 29/6 = 4 5/6 ounces
Therefore, Siobhan will need 1/2 cup of heavy whipping cream and 4 5/6 ounces of sweetened condensed milk for 4 servings.
not 1/2
Jay rode his bike 48 miles in 2 2/5 hours, and Maria rode her bike 60 miles in 3 1/3 hours. What was each person’s speed in miles per hour? Express the answers in simplest form.
To find the speed in miles per hour, we need to divide the distance traveled by the time taken.
For Jay:
Speed = Distance / Time = 48 miles / 2 2/5 hours
To divide the mixed number by a whole number, we convert the mixed number to an improper fraction.
2 2/5 = (2 * 5 + 2)/5 = 12/5
Speed = 48 miles / (12/5) hours
To divide by a fraction, we invert the fraction and multiply.
Speed = 48 miles * (5/12) hours = (48 * 5) miles / 12 hours = 240 miles / 12 hours
Simplifying further, we divide both the numerator and denominator by their greatest common divisor (GCD), which is 12.
Speed = 240/12 = 20 miles/hour
For Maria:
Speed = Distance / Time = 60 miles / 3 1/3 hours
3 1/3 = (3 * 3 + 1)/3 = 10/3
Speed = 60 miles / (10/3) hours
Speed = 60 miles * (3/10) hours = (60 * 3) miles / 10 hours = 180 miles / 10 hours
Simplifying, we divide both the numerator and denominator by their GCD, which is 10.
Speed = 180/10 = 18 miles/hour
Therefore, Jay's speed was 20 miles per hour and Maria's speed was 18 miles per hour.
Kimi has a part-time job tutoring students in math for 40 hours each month. She will be tutoring one student for 1/4 of the allotted time this month and another student for 3/8 of the allotted time this month. How many hours of tutoring will she be able to provide to other students this month? Solve this multi-step real-world problem involving multiplication with fractions. Express the answer in simplest form.
To find the number of hours of tutoring Kimi will be able to provide to other students this month, we need to subtract the time she will spend tutoring the two specified students from the total allocated time.
Total allocated time: 40 hours
Time tutoring the first student: 1/4 * 40 hours = (1/4) * 40 = 10 hours
Time tutoring the second student: 3/8 * 40 hours = (3/8) * 40 = 15 hours
To find the time available for other students, we subtract the time tutoring the two specified students from the total allocated time:
Time available for other students = Total allocated time - Time tutoring the first student - Time tutoring the second student
Time available for other students = 40 hours - 10 hours - 15 hours = 40 hours - 25 hours = 15 hours
Therefore, Kimi will be able to provide 15 hours of tutoring to other students this month.
Mr. O’Donnell has $500 budgeted to donate to charity. He gave 2/5 of the amount to the Red Cross. Mr. O’Donnell donated 1/3 of the remainder to Special Olympics. How much is left to give to other charities?
To find out how much is left to give to other charities, we need to subtract the amount donated to the Red Cross and the amount donated to Special Olympics from the total budget.
Total budget: $500
Amount donated to the Red Cross: (2/5) * $500 = $200
Remaining amount after donating to the Red Cross: $500 - $200 = $300
Amount donated to Special Olympics: (1/3) * $300 = $100
Amount left to give to other charities: $300 - $100 = $200
Therefore, Mr. O’Donnell has $200 left to give to other charities.