The pH of pure water at 50C is 6.63. What is the value of Kw at 50C
The value of Kw at any temperature can be calculated using the equation:
Kw = [H+][OH-]
Since the pH of pure water is 7 at 25°C, we know that [H+] = 10^-7 M. At 50°C, we can calculate the value of [H+] using the equation:
pH = -log[H+]
Rearranging the equation, we get:
[H+] = 10^(-pH)
Substituting the given pH value:
[H+] = 10^(-6.63)
[H+] = 2.095 x 10^(-7) M
Since water is neutral, we also know that [H+] = [OH-]. Therefore, the value of Kw at 50°C is:
Kw = (2.095 x 10^(-7))(2.095 x 10^(-7))
Kw = 4.38 x 10^(-14)