Question
Use the image to answer the question.
An illustration shows a square pyramid with labeled parts. The front and left faces of the pyramid and base are visible. The back and right faces are not visible. The back and right base edges are not visible but their position is indicated by a dashed line. The left base edge shows a length of 16 feet. A dotted line extends from the interior of the vertex straight down to the center of the base and shows a height of 15. A right angle is indicated where the dotted height line meets the base.
Find the slant height of the square pyramid.
(1 point)
Unfortunately, without the image it is not possible to provide an accurate answer.
but i gave you a description of the pyramid.
Apologies for the confusion. Based on the description provided, we can calculate the slant height of the square pyramid using Pythagoras' theorem.
The height of the pyramid is given as 15 feet, and the length of the base is given as 16 feet. Since the slant height is the hypotenuse of a right triangle formed by the height and the slant height, we can find the slant height (s) using the formula:
s^2 = h^2 + b^2
where h is the height and b is half the length of the base.
In this case, h = 15 feet and b = 8 feet (half of 16 feet). Plugging these values into the equation, we get:
s^2 = 15^2 + 8^2
s^2 = 225 + 64
s^2 = 289
So, the square of the slant height is 289. Taking the square root of both sides, we get:
s = √289
s = 17 feet
Therefore, the slant height of the square pyramid is 17 feet.