a ball is thrown into the air with an initial upward velocity of 60 ft/s. its height (h) in feet after t seconds id given by the function h=-16t^2+60t+6. what will the height be at t=3 seconds?
A ) 35 feet
B ) 40 feet
C ) 42 feet
D ) 45 feet
To find the height at t=3 seconds, we substitute t=3 into the equation h=-16t^2+60t+6:
h = -16(3)^2 + 60(3) + 6
h = -16(9) + 180 + 6
h = -144 + 180 + 6
h = 186 - 144
h = 42
Therefore, the height at t=3 seconds is 42 feet.