Use the electronegativity and valence electron information to answer the question. H electronegativity: 2.2 H valence electrons: 1 C electronegativity: 2.55 C valence electrons: 4 O electronegativity: 3.44 O valence electrons: 6 Chemical weathering over hundreds of thousands of years formed modern caves. One form of chemical weathering occurs when carbon dioxide reacts with water to produce carbonic acid, H2CO3. How many bonds formed in H2CO3? (1 point) Responses eight eight five five six six three
H2CO3 is formed by the reaction of carbon dioxide (CO2) with water (H2O).
Carbon dioxide (CO2) has one carbon (C) atom and two oxygen (O) atoms.
Carbon (C) has a valence of 4, and oxygen (O) has a valence of 6.
To determine the number of bonds formed in H2CO3, we calculate the total number of valence electrons in the molecule.
For hydrogen (H), which has a valence of 1, and with two hydrogen (H) atoms in H2CO3, we have:
2 Hydrogen (H) x 1 valence electron = 2 valence electrons.
For carbon (C), which has a valence of 4, we have:
1 Carbon (C) x 4 valence electrons = 4 valence electrons.
For oxygen (O), which has a valence of 6, and with three oxygen (O) atoms in H2CO3, we have:
3 Oxygen (O) x 6 valence electrons = 18 valence electrons.
Adding up the number of valence electrons, we have:
2 + 4 + 18 = 24 valence electrons.
To form chemical bonds, each atom in the molecule typically requires 8 valence electrons (except hydrogen, which only needs 2).
As H2CO3 has 24 valence electrons, we divide by 8 to determine the number of bonds formed:
24 valence electrons / 8 valence electrons per bond = 3 bonds.
Therefore, there are 3 bonds formed in H2CO3.