what is the standard from of a point that passes through 0,6 and -4,4
The standard form of a linear equation is given by Ax + By = C, where A, B, and C are constants.
To find the equation of a line passing through the points (0, 6) and (-4, 4), we need to determine the values of A, B, and C.
First, let's find the slope (m) of the line:
m = (y2 - y1) / (x2 - x1)
m = (4 - 6) / (-4 - 0)
m = (-2) / (-4)
m = 1/2
Now, we can use the point-slope form of a linear equation:
y - y1 = m(x - x1)
Using the point (0, 6), we have:
y - 6 = (1/2)(x - 0)
y - 6 = (1/2)x
To convert this to the standard form, we multiply by 2 to eliminate the fraction:
2y - 12 = x
Rearranging the terms, we get:
x - 2y = -12
Thus, the standard form of the equation of the line passing through (0, 6) and (-4, 4) is x - 2y = -12.