Use the galvanic cell reaction to answer the question. 2Cr(s) + 3Cu2+(aq) → 2Cr3+(aq) + 3Cu(s) Which half reaction occurs at the cathode? (1 point) Responses 3Cu2+(aq) + 2e– → 3Cu(s) 3Cu 2+ ( aq ) + 2e – → 3Cu( s ) 3Cu2+(aq) + 6e– → 3Cu(s) 3Cu 2+ ( aq ) + 6e – → 3Cu( s ) 2Cr(s) → 2Cr3+(aq) + 3e– 2Cr( s ) → 2Cr 3+ ( aq ) + 3e – 2Cr(s) → 2Cr3+(aq) + 6e–

The half reaction that occurs at the cathode is: 3Cu2+(aq) + 2e– → 3Cu(s)