Use Pascal's Triangle to expand the binomial.
(d-3)^6
(1 point)
- d^6 - 18d^5 + 135d^4 - 540d^3 + 1,215d^2 - 1,458d + 729
- d^6 + 18d^5 + 135d^4 + 540d^3 + 1,215d^2 + 1,458d + 729
- d^6 - 6d^5 + 15d^4 - 20d^3 + 15d^2 - 6d + 1
- d^6 + 6d^5 + 15d^4 + 20d^3 + 15d^2 + 6d + 1
The correct expansion of (d-3)^6 using Pascal's Triangle is:
- d^6 + 18d^5 - 135d^4 + 540d^3 - 1,215d^2 + 1,458d - 729