The waiting time at an elevator is uniformly distributed between 30 and 200 seconds. Find the mean and standard deviation of the waiting time.
1 point
115 seconds and 49.07 seconds
000
1
115 seconds and 2408.3333 (second)2
1.15 minutes and 24.08333 (minute)2
2 23 3
4
5
6
7
8
9
1.15 minutes and 0.4907 minutes
To find the mean of a uniformly distributed variable, you need to take the average of the minimum and maximum values. In this case, the minimum waiting time is 30 seconds and the maximum waiting time is 200 seconds.
So, the mean waiting time is (30+200)/2 = 115 seconds.
To find the standard deviation of a uniformly distributed variable, you can use the formula:
standard deviation = (maximum - minimum) / sqrt(12)
In this case, the minimum waiting time is 30 seconds and the maximum waiting time is 200 seconds.
So, the standard deviation is (200 - 30) / sqrt(12) ≈ 49.07 seconds.
Therefore, the correct answer is 115 seconds and 49.07 seconds.