A 100 kg box is at rest before a student pushes it across the floor at a velocity of 3 m/s. Calculate the work being transferred onto the box by the student.(1 point) Responses 450 J 33.33 J 150j
The work being transferred onto the box by the student can be calculated using the formula:
Work = Force * Distance
In this case, the force is the force applied by the student to push the box, and the distance is the distance the box is pushed.
Since the box is at rest before being pushed, the initial velocity (u) is 0 m/s. The final velocity (v) is 3 m/s.
Using the equation of motion v^2 = u^2 + 2as, where v is the final velocity, u is the initial velocity, a is the acceleration, and s is the distance:
(3 m/s)^2 = (0 m/s)^2 + 2(a)(s)
9 m^2/s^2 = 0 m^2/s^2 + 2(a)(s)
a = 4.5 m/s^2
Now we can calculate the force using Newton's second law:
Force = mass * acceleration
Force = 100 kg * 4.5 m/s^2
Force = 450 N
Finally, we can calculate the work:
Work = Force * Distance
Work = 450 N * 1 m (assuming a distance of 1 meter is pushed)
Work = 450 J
Therefore, the work being transferred onto the box by the student is 450 J.