What is the cell potential of an electrolytic cell made of Al^3+(aq) and Cd(s)?
In order to determine the cell potential of an electrolytic cell made of Al^3+(aq) and Cd(s), we need to know the reduction potentials of each half-reaction.
The half-reaction for the reduction of Al^3+(aq) can be written as:
Al^3+(aq) + 3e^- → Al(s) E°red = -1.66 V
The half-reaction for the oxidation of Cd(s) can be written as:
Cd(s) → Cd^2+(aq) + 2e^- E°ox = -0.40 V
To calculate the cell potential, we subtract the reduction potential of the oxidation half-reaction from the reduction potential of the reduction half-reaction:
Cell potential (E°cell) = E°red - E°ox
E°cell = (-1.66 V) - (-0.40 V)
E°cell = -1.26 V
Therefore, the cell potential of an electrolytic cell made of Al^3+(aq) and Cd(s) is -1.26 V.