15+23+44-55+10, where all the numbers are in base 6 system, giving your answer in the same system
To solve this expression, we need to convert all the numbers into base 10 first, perform the arithmetic operations, and finally convert the result back into base 6.
Converting the numbers into base 10:
15 (base 6) = 1*(6^1) + 5*(6^0) = 11 (base 10)
23 (base 6) = 2*(6^1) + 3*(6^0) = 15 (base 10)
44 (base 6) = 4*(6^1) + 4*(6^0) = 28 (base 10)
55 (base 6) = 5*(6^1) + 5*(6^0) = 35 (base 10)
10 (base 6) = 1*(6^1) + 0*(6^0) = 6 (base 10)
Now, performing the arithmetic operations in base 10:
11 + 15 + 28 - 35 + 6 = 25
Finally, converting the result back into base 6:
25 (base 10) = 4*(6^1) + 1*(6^0) = 41 (base 6)
Therefore, 15 + 23 + 44 - 55 + 10 (in base 6) is equal to 41 (base 6).