if the tv us 60inchs and the height is 30 inchs what is the width in inchs?
To find the width of the TV, we can use the Pythagorean theorem:
width^2 + height^2 = diagonal^2
Let's denote the width as 'w' and the diagonal as 'd':
w^2 + 30^2 = 60^2
Simplifying the equation:
w^2 + 900 = 3600
Subtracting 900 from both sides:
w^2 = 2700
Taking the square root of both sides:
w = √2700
w ≈ 51.96
Therefore, the width of the TV is approximately 51.96 inches.
if the tv us 52 inchs and the width is 45 inchs? inchs what is the hight in inchs?
To find the height of the TV, we already know the width and diagonal. We can use the Pythagorean theorem:
height^2 = diagonal^2 - width^2
Let's denote the height as 'h' and the diagonal as 'd':
h^2 = 52^2 - 45^2
Simplifying the equation:
h^2 = 2704 - 2025
h^2 = 679
Taking the square root of both sides:
h = √679
h ≈ 26.06
Therefore, the height of the TV is approximately 26.06 inches.
if the height is 20 inchs and the width is 35 what if the over all inches?
To find the overall size of the TV, we can use the formula for calculating the diagonal length of a rectangle:
diagonal^2 = height^2 + width^2
Let's denote the diagonal as 'd':
d^2 = 20^2 + 35^2
Simplifying the equation:
d^2 = 400 + 1225
d^2 = 1625
Taking the square root of both sides:
d = √1625
d ≈ 40.31
Therefore, the overall size (diagonal length) of the TV is approximately 40.31 inches.