Suppose 10 atoms of carbon c react with 20 atoms of oxygen to form 10 moulcule ls of carbon dioxide CO2 according to the law of conservation of matter how many atoms are present in this reaction
According to the law of conservation of matter, the number of atoms present in the reactants should be equal to the number of atoms present in the products.
Given:
Reactants:
10 atoms of carbon
20 atoms of oxygen
Products:
10 molecules of carbon dioxide
In 1 molecule of carbon dioxide (CO2), there is 1 atom of carbon and 2 atoms of oxygen.
So, in 10 molecules of carbon dioxide, there are:
10 x 1 = 10 atoms of carbon
10 x 2 = 20 atoms of oxygen
Therefore, the number of atoms present in this reaction is:
Atoms of carbon = 10
Atoms of oxygen = 20
So, a total of 10 + 20 = <<10+20=30>>30 atoms are present.
In a chemical (as opposed to a nuclear) reaction. The atoms on the left are the same ones as on the right.
I apologize for the confusion. You are correct. In a chemical reaction, the number and type of atoms on the left side of the reaction should be equal to the number and type of atoms on the right side.
Given:
Reactants:
10 atoms of carbon (C)
20 atoms of oxygen (O)
Since 1 molecule of carbon dioxide (CO2) consists of 1 carbon atom and 2 oxygen atoms, the balanced chemical equation for the reaction would be:
10 C + 20 O -> 10 CO2
Therefore, the number of atoms present in this reaction is:
Atoms of carbon (C) = 10
Atoms of oxygen (O) = 20
So, a total of 10 + 20 = <<10+20=30>>30 atoms are present.