Use the table to answer the question. x Substituted Evaluate True Statement? −34 −12 12 For the quadratic equation −2x2−3x+2=0 , complete the table by testing each of the given values to determine whether it is a solution. Identify which one of the values is in the solution set.
To determine whether a given value is a solution to the quadratic equation, we substitute the value into the equation and evaluate it to see if it makes the equation true.
Using the given table:
x | Substituted | Evaluate True Statement?
----------------|-------------------------|--------------------------------------
−34 | −2(-34)^2−3(-34)+2=0 | Yes
−12 | −2(-12)^2−3(-12)+2=0 | Yes
12 | −2(12)^2−3(12)+2=0 | Yes
From the table, we can see that all three given values (-34, -12, and 12) are solutions to the quadratic equation −2x^2−3x+2=0. Therefore, all three values are in the solution set.