2C12H4CI6+23O2+2H2O->24CO2+12HCI (a) how many moles of water are needed to react with 12.8 mol O2?
From the balanced chemical equation, we can see that 23 moles of O2 react with 2 moles of water.
To find out how many moles of water are needed to react with 12.8 moles of O2, we can set up a proportion:
(23 moles O2) / (2 moles H2O) = (12.8 moles O2) / (x moles H2O)
Cross multiplying gives us:
23 moles O2 * x moles H2O = 2 moles H2O * 12.8 moles O2
23x = 25.6
Divide both sides of the equation by 23 to solve for x:
x = 25.6 / 23
x = 1.113 moles H2O
Therefore, 1.113 moles of water are needed to react with 12.8 moles of O2.