Subtract: (3b2c) (2b+6c)(b+c) (1 point)
To subtract (3b+2c) from (2b+6c)(b+c), we need to distribute the -1 to each term inside the parentheses. This gives us:
(2b+6c)(b+c) - (3b+2c)
Next, we can use the distributive property to expand the equation:
(2b)(b) + (2b)(c) + (6c)(b) + (6c)(c) - 3b - 2c
Simplifying this expression further, we get:
2b^2 + 2bc + 6bc + 6c^2 - 3b - 2c
Combining like terms, we have:
2b^2 + 8bc + 6c^2 - 3b - 2c
So the final answer is 2b^2 + 8bc + 6c^2 - 3b - 2c.